25510 = 111111112
25510 = 001001010101BCD
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The number 47 in binary would be 101111
'2' Decimal code => '10' Binary code.
Binary code of 4 is 0100. To get Excess-3 code, add 11(binary code of 3) to binary code of desired number, here it is 4. Hence, Excess-3 Code for 4 is 0111.
1111 in binary is 15 in decimal.
Ah, what a lovely question! The binary code for 2 is 10. Just like painting, binary code is a beautiful language that computers use to communicate. Keep exploring and learning, my friend!