You need to measure the mass using appropriate equipment. You can measure the volume of a textbook and a container of milk by measuring its linear dimensions and calculating the volume.
It is not at all easy to measure the volume of an air balloon. You cannot use displacement of a fluid (water) because when submerged, the balloon would be experiencing water pressure and so would occupy a smaller volume. You cannot measure it by allowing the air to escape and measure that volume of air because that air will no longer be experiencing the pressure exerted by the material (rubber?) of the balloon. I have no answer to this part.
Once you have the mass and volume, the density is merely mass/volume.
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density = mass/volume Determine the volume of the screw by using the water displacement method (see related link below). Determine the mass of the screw on a balance or scale. Divide the mass by the volume, and that will be the density.
0.75 kg/L
The same way you determine the density of any other object. Divide the mass by the volume. Add: density = mass/volume = 5g/1mL = 5g/mL = 5g/cm3* *1mL = 1 cm3
This varies greatly with the size of the banana in question. Determine the volume of the banana using water displacement. Determine the mass of the banana on a balance. Density = mass/volume
You can lower the density of hydrogen (or any) gas by heating it in a container where it is free to expand, like a balloon.
You cannot. Density = Mass/Volume. You have only volume, no mass and so there is no way to determine density.
Density of any balloon depends on the material of the balloon and how much the balloon is filled.
To determine the density of an object, you need its mass and volume. If the object is oddly shaped, you can determine its volume by measuring the volume of water displaced when thee object is submerged in a container of water.
because as you heat the gas, you cause the gas to expand on the container (whish is a balloon), this lowers the density, and a less dense fluid submersed in a denser fluid will rise, like an air bubble rises from underwater
after you let several liquids (each with a different density) sit in a container for a while, the greater the density, the farther down the liquid is in a container
because helium has less density
Water displacement method will work fine with molecules that do not dissolve... Here you have something that will dissolve in water, changing it's density. What I would do is to weight a graduated container, put some sugar (more you add, more precise will be the result) in the container... Better weight the container before... Weight the container after. Now you know the *weight* part of the answer, then you melt it, in that container... you read the *volume* part of the answer. put the part together to have a density which is mass/volume g/cm³ for example, or g/mL, which is the same.
No it decreases
When the temperature is decreased! :)
The balloon with krypton gas has a higher density than the balloon with argon gas.
No, density will be the same when cooling in a fixed container (pressure will drop, mass and volume unchanged)Yes, density will increase in an flexible balloon (volumewill decrease, mass and presure constant)Yes, density will be increased in cooler open air (increased mass in the same volume).