[2(9 + 7)] - 8 = (2 x 16) - 8 = 32 - 8 = 24
It is: (8-2)*(7-3) = 24
3 4 7 8 : [(7-3)× 4] + 8 as in 7 - 3 = 4 then that 4 x 4 = 16 and 16 + 8 = 24
2/3 and 7/8, find the least common denominator which is 24, then 2/3 = 16/24 and 7/8 = 21/24 and so 7/8 is greater than 2/3
1) 8*1+8+6 = 24 2) 8*(8-6+1)=24
52 - 8 + 7 = 25 - 8 + 7 = 24
Assuming all of {7, 8, 2, 3} have to be used exactly once: (8 - 2) x (7 - 3) = 24.
8 because 3*8 = 24 and 7*8 = 56
[2(9 + 7)] - 8 = (2 x 16) - 8 = 32 - 8 = 24
Well if you dont use the 2 you'll get the answer of 24 by adding 9+7+8
(7 - (8 ÷ 8)) × 4 = 24
Yes, it is possible to make 24 using the numbers 9, 8, 7, and 5. One way to do this is by multiplying 9 by (8 ÷ (7 - 5)), which simplifies to 9 * (8 ÷ 2) = 36 ÷ 2 = 18. Then, subtract 18 from 9 to get 24.
It could be: 8*(9-7)+8 = 24
(7 + 2) × 8 ÷ 3 = 24
(5+7)*(8-6)=24
It is: 52-8+7 = 24
To make 24 using the numbers 7, 9, 6, and 8, you can use the following equation: (9 - 6) x (8 - 7) = 3 x 1 = 3. Then, add 9 to this result: 3 + 9 = 12. Finally, multiply this result by 2: 12 x 2 = 24.