3
It is the circular disc with centre at the origin and radius = 3 units.
Assuming the equation is x2 - y2 - 6x - 2y = 60this is equivalent tox2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1= (x - 3)2 - (y + 1)2 = 68Assuming the equation is x2 - y2 - 6x - 2y = 60this is equivalent tox2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1= (x - 3)2 - (y + 1)2 = 68Assuming the equation is x2 - y2 - 6x - 2y = 60this is equivalent tox2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1= (x - 3)2 - (y + 1)2 = 68Assuming the equation is x2 - y2 - 6x - 2y = 60this is equivalent tox2 - 6x + 9 - y2 - 2y - 1 = 60 + 9 - 1= (x - 3)2 - (y + 1)2 = 68
The equation to figure out a slope is y1 - y2 / x1 - x2. In (1,9) and (-3,16), 9 is y1 and 16 is y2. 1 is x1 and -3 is x2. Now you have -7/4, which is your slope!
9 (APEX)
Draw a circle with its center at the origin and a radius of 3.
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
X2 or 2 times x?
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
If you want to have an center point of zero you use the equation x2+y2=r2. In this case x2+y2=9.
3
9
3 (which is the sqrt of 9)
9
It is the circular disc with centre at the origin and radius = 3 units.
When graphing, you typically want an equation in the form y = f(x). To convert your equation for a circle to this form: Y2 + X2 = 9 Y2 = 9-X2 Y=sqrt(9-X2) This equation will not look like a circle when it is graphed because the square root of any real number is always positive, so only the positive half of the circle will be graphed.
x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)