9 + 11 = 20... 19 - 4 = 15... 15 x 20 = 300... 300 - 6 = 294 !
5 + 6 = 11 6 + 5 = 11 11 - 6 = 5 11 - 5 = 6
11 + (19 + 6) = 36(11 + 19) + 6 = 36So they are both equal. The brackets make no difference in this case.
11 is a prime number and has no prime factors other than itself.
6/(1-3/4)=24
You take 6 and make a rectangle which is a square and take one of the 5 sticks break it in 2 to make 6 which you can make another square or rectangle easy
3x4=12x6=72-6=66-6=60
6+6-1=11
You can make 9 triangles but NOT rectangles.
9 + 11 = 20... 19 - 4 = 15... 15 x 20 = 300... 300 - 6 = 294 !
One possibility - I'm sure there are others, is : 32 + 8 - 6 = 9 + 2 = 11
ooh 11-8=3 3*10=30 30-6=24 tadaa this one took me some thinking
By using all six match sticks only once the maximum number of Roman numerals that can be made are three i.e. I, II and III (1, 2 and 3).
It takes one matchstick to make the "I" symbol, two to make the "V" symbol, two to make the "X" symbol, two to make the "L" symbol, and four to make the "M" symbol (I'm excluding "C" and "D" as they are curved shapes). I got 45 without multiplication... I - (1) II, V, X, L - (4) III, IV, VI, IX, XI, LI - (6) VII, XII, XV, XX, XL, XII, LV, LX, M - (9) VIII, XIII, XIV, XVI, XIX, XXI, XLI, LIV, LVI, LIX, LXI, MI - (12) XVII, XXII, XXV, XXX, XLII, LVII, LXI, LXV, LXX, MII, MV, MX, ML - (13) Although the above doesn't include the fact that some Roman numerals can be multiplied by 1,000 by adding a single horizontal line over them, which gives additional symbols to work with: Three sticks: (V), (L), (X) - (3) Four sticks: (IV), (VI), (IX), (XI) - (4) Five sticks: (M), (VII), (XII), (XV), (XX), (XL), (LV), (LX) - (8) Six sticks: (VIII), (XIII), (XIV), (XVI), (XIX), (XXI), (XLI), (LIV), (LVI), (LIX), (LXI), (MI) - (12) For a total of 27 more symbols. Using the info from the first part makes this easier - anything using three sticks can be combined with anything using one, two, or three sticks, which makes for (3*11) more numbers. Anything with four sticks can be combined with anything using one or two sticks, which makes for (4*5) more choices. Anything using five sticks can be combined with anything using one stick, which makes for (8*1) more choices. So, in total: 45 + 27 + (3*11) + (4*5) + (8*1) = 133
put sticks in 6 boxes but keep the top emty
2*(6/6 + 11) = 2*(1 + 11) = 2*12 = 24. Simple!
If you know that, 6 x 11 = 66, then this can be rearranged to make 66/11 = 6