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That depends on the answer required.

If it's 11 then each digit can be made from 3 sticks

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Q: How can you make 11 answer using 6 sticks?
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How do you make two squares with 11 straws?

You take 6 and make a rectangle which is a square and take one of the 5 sticks break it in 2 to make 6 which you can make another square or rectangle easy


How do you make 60 using 3 4 and 6 without using them over 11 times?

3x4=12x6=72-6=66-6=60


How does 6 and 6 make 11?

6+6-1=11


How do you make 9 rectangles with only 6 popsicle sticks?

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How do you make 294 using 9 4 6 11 19?

9 + 11 = 20... 19 - 4 = 15... 15 x 20 = 300... 300 - 6 = 294 !


Using all of the following four numbers 2 3 6 and 8 is it possible to make 11?

One possibility - I'm sure there are others, is : 32 + 8 - 6 = 9 + 2 = 11


How do you make 24 out od using 8 6 10 and 11?

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How many roman numerals can be made using 6 match sticks?

By using all six match sticks only once the maximum number of Roman numerals that can be made are three i.e. I, II and III (1, 2 and 3).


How many roman numerals can be made using 6 matchsticks?

It takes one matchstick to make the "I" symbol, two to make the "V" symbol, two to make the "X" symbol, two to make the "L" symbol, and four to make the "M" symbol (I'm excluding "C" and "D" as they are curved shapes). I got 45 without multiplication... I - (1) II, V, X, L - (4) III, IV, VI, IX, XI, LI - (6) VII, XII, XV, XX, XL, XII, LV, LX, M - (9) VIII, XIII, XIV, XVI, XIX, XXI, XLI, LIV, LVI, LIX, LXI, MI - (12) XVII, XXII, XXV, XXX, XLII, LVII, LXI, LXV, LXX, MII, MV, MX, ML - (13) Although the above doesn't include the fact that some Roman numerals can be multiplied by 1,000 by adding a single horizontal line over them, which gives additional symbols to work with: Three sticks: (V), (L), (X) - (3) Four sticks: (IV), (VI), (IX), (XI) - (4) Five sticks: (M), (VII), (XII), (XV), (XX), (XL), (LV), (LX) - (8) Six sticks: (VIII), (XIII), (XIV), (XVI), (XIX), (XXI), (XLI), (LIV), (LVI), (LIX), (LXI), (MI) - (12) For a total of 27 more symbols. Using the info from the first part makes this easier - anything using three sticks can be combined with anything using one, two, or three sticks, which makes for (3*11) more numbers. Anything with four sticks can be combined with anything using one or two sticks, which makes for (4*5) more choices. Anything using five sticks can be combined with anything using one stick, which makes for (8*1) more choices. So, in total: 45 + 27 + (3*11) + (4*5) + (8*1) = 133


How can 2 6 6 11 equal 24 using each number once?

2*(6/6 + 11) = 2*(1 + 11) = 2*12 = 24. Simple!


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