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It doesn't. It varies inversely as that square root.

Here's how I did it:

T = time for a planet's revolution

R = mean distance from the sun

K = some konstant, any konstant

V = planet's linear speed

Kepler's 3rd law: T2/R3 = K . . . . . T2 = K R3

But T = orbital circumference/V , so (2 pi R/V)2 = K R3 , and (2 pi/V)2 = K R

Divide ' 1 ' by each side:

(V/2 pi)2 = 1/K R or V2 = 1/K R (new konstant)

V = K sqrt( 1/R )

qed

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Q: How can you prove by using Kepler's Law that the linear velocity of a planet varies as the square root of the mean distance from the Sun?
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