Show that corresponding angles are congruent?
By using a protractor which will show that corresponding angles are equal and alternate angles are equal .
Not too sure about the given description but they could be equal alternate angles.
ok
Parallelogram and a rectangle
Two points determine a line. Also there is one and only line perpendicular to given line through a given point on the line,. and There is one and only line parallel to given line through a given point not on the line.
If the lines have the same slope but with different y intercepts then they are parallel
By using a protractor which will show that corresponding angles are equal and alternate angles are equal .
Any line that is not parallel to the given lines. The transversal that contains the shortest distance between the two parallel lines, is perpendicular to them.
Transversal lines are not parallel and so have a gradient that is different to that of the given lines.
One way is to draw a straight line from the constructed line to the given line. If the lines are parallel, than the acute angle at the given and constructed line will be the same as will be the obtuse angles at the given and constructed line.
Parallel
Given two lines cut by a transversal, if corresponding angles are congruent, then the lines are parallel.
Given two lines cut by a transversal, if corresponding angles are congruent, then the lines are parallel.
Lines are parallel if they are perpendicular to the same line. Since the lines m and l are parallel (given), and the line l is perpendicular to the line p (given), then the lines m and p are perpendicular (the conclusion).
Not too sure about the given description but they could be equal alternate angles.
Take any two lines and look at their slopes. -- If the slopes are equal, then the lines are parallel. -- If the product of the slopes is -1, then the lines are perpendicular.
It's the theorem that says " One and only one perpendicular can be drawn from a point to a line. "