If you can cut it in half three times and get a whole number each time, it's divisible by 8.
just dividing it
1. Sum of digits (12) is divisible by 3, so number is divisible by 3 2. It's an even number so it's divisible by 2 3. If it's divisible by both 3 and 2 then it's divisible by 3 x 2, ie 6.
There is not an easy way without some division. The simplest is to check the divisibility of the number formed by the last three digits.
You can tell if the last 2 digits of the number can be divisible by 4 or 8. So the number 3156372856374856386578365864would be divisible by 8 because 8 can go into 64.
I think the question is mistyped, and should be "Is 414 evenly divisible by 3?" i.e. does it divide by 3 without leaving a remainder. The answer is yes. A quick way to tell if a number is divisible by 3 is to add the digits and if the total is divisible by 3, then the number in question is also divisible by 3 4 + 1 + 4 = 9 and 9 is divisible by 3 414 ÷ 3 = 138
just dividing it
1. Sum of digits (12) is divisible by 3, so number is divisible by 3 2. It's an even number so it's divisible by 2 3. If it's divisible by both 3 and 2 then it's divisible by 3 x 2, ie 6.
There is not an easy way without some division. The simplest is to check the divisibility of the number formed by the last three digits.
To determine if a number is even or odd, you can check if the number is divisible by 2. If the number is divisible by 2 without leaving a remainder, then it is even. If the number is not divisible by 2 or leaves a remainder when divided by 2, then it is odd.
You can tell if the last 2 digits of the number can be divisible by 4 or 8. So the number 3156372856374856386578365864would be divisible by 8 because 8 can go into 64.
506
Because it's not exactly divisible by 3.
If you know the rules of divisibility, you can tell if a number is divisible by another number by looking at it. A number is divisible... by 2 if it's even. by 3 if the sum of its digits is a multiple of 3. by 4 if the last two digits are a multiple of 4. by 5 if it ends in a 5 or 0. by 6 if it's divisible by 2 and 3. by 8 if the last three digits are divisible by 8. by 9 if the sum of its digits is a multiple of 9. by 10 if it ends in a 0. There is a rule for 7, but it's annoyingly complicated, hard to remember and takes as long to implement as actually dividing by 7.
divisible of 4,2,1
If it's even and divisible by 3, it's divisible by 6.
If it ends in a zero, which it does, it is divisible by 5.
No remainder because the digits of 45549 finally add up to 9