You could take away groups of 5 from the original 25 until nothing was left. Then you could count how many groups of 5 you now have. This will then tell you what 25 divided by 5 is.
So we start with 25.
We create one group of 5 leaving 20 behind.
The second group of 5 leaves 15 behind now.
Then 10 are left.
Then only 5.
Then the fifth and last group leaves behind 0.
So we have five groups of 5 things. As there are none left in the original 25 we can see that 5 lots of 5 is equal to 25. Therefore 25 / 5 = 5.
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To divide 52 evenly into groups, you would need to find the factors of 52. The factors of 52 are 1, 2, 4, 13, 26, and 52. Therefore, you can divide 52 evenly into groups in 6 ways: (1, 52), (2, 26), (4, 13), (13, 4), (26, 2), and (52, 1).
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To divide 30 students into groups of the same size, you would need to find a common factor of 30 that represents the desired group size. The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30. Therefore, you could divide the 30 students into groups of 2, 3, 5, 6, 10, 15, or 30 students each. Each group would have an equal number of students, ensuring fairness in the division.
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Oh, dude, you're hitting me with some math here. So, like, 145 divided into equal groups means you're breaking up 145 into smaller, equal parts. If you divide 145 by, say, 5, each group would have 29 in it. It's like slicing up a pizza, but with numbers.