0
Assuming you mean it repeats indefinitely, you call your number "x", and write:x = 0.66666...
10x = 6.66666...
You subtract the first equation from the second, then solve the resulting equation for "x".
Note: In other cases, if two digits repeat, you multiply by 100 to get the second equation; if three digits repeat, you multiply by 1000, etc.
Wiki User
∙ 8y ago
Wiki User
∙ 8y ago0.6666 repeating = 2/3
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