To calculate the decimal value of a bit string:
Number the bits from right to left 0 - n.
Starting with a decimal value of 0, add 2^(Number of that digit) for each 1 you see in your bit string.
The sum is the decimal equivalent to the binary number.
The number of different bit strings of length 7 can be calculated using the formula 2^n, where n is the length of the bit string. In this case, with a length of 7, there are 2^7 = 128 different bit strings possible. This is because each bit in the string can have 2 possible values (0 or 1), and there are 7 bits in total.
-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.
n+1 (counting the empty string)
You are essentially asking how many different bit strings of length 9 are there, as the first 3 bits are fixed. The answer is 2^9 = 512.
Three of the bits are already determined. That leaves 5 .25 = 32
Every bit can either be a 0 or 1. So to find the amount of bit strings of length either, you do 2length to find the amount of bit strings there are of a given length.
72
1024
The number of different bit strings of length 7 can be calculated using the formula 2^n, where n is the length of the bit string. In this case, with a length of 7, there are 2^7 = 128 different bit strings possible. This is because each bit in the string can have 2 possible values (0 or 1), and there are 7 bits in total.
210=1024
-- There are 256 bit strings of length 8 . -- There are 4 bit strings of length 2, and you've restricted 2 of the 8 bits to 1 of those 4 . -- So you've restricted the whole byte to 1/4 of its possible values = 64 of them.
Half of them.
There are no zero-length strings that start with 1 bit or end with 2 bits. In a zero-length string, there are no bits at all.
The voltage distribution across insulator strings is not equal, this because exist capacitances beteween insulators and tower and between insulators and conductor. So how i can calculate the stray capacitances across insulator strings?
There are 210.
1024 of them.
The main bit is the body, the bit of wood that holds up the strings is the bridge. those are in the middle of the violin, but can you be more specific?