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You need the perimeter but the area of the home is not sufficient to identify its perimeter.

All that can be said is that, in the unlikely event that the home is circular, the perimeter will be 142 feet. For any other shape it will be more. And it can be infinitely more.

Suppose the home is rectangular, with length = L feet and width = W feet.

Then for an area of 1600 sq feet, W must be 1600/L feet

Therefore the perimeter, P = 2*(L+W) = 2L + 3200/L feet.

If L = 80 ft, then W = 20 ft and P = 200 ft

L = 100 ft then W = 16 ft and P = 232 ft

L = 160 ft , W = 10 ft and P = 340 ft

You can go further:

L = 1600 ft, W = 1 ft P = 3202 ft

L = 1.6 million ft, W = 0.001 ft and P = 320000.002 ft

L = 1.6 billion ft, W = 0.000001 ft and P = 606060.60.. MILES!

As you can see, there is no limit!

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11y ago
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Q: How do you calculate linear feet on a 1600 square foot home for gutters?
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