each pair is a double i.e. 14 and 28, 18 and 36, 26 and 52 and so on. Each successive pair is increased by double the last increase. So looking at every other number, 14+4=18 18+8=26 26+16=42 so the next pair would be 42+32=74 and its double 148
Another way to think of it is the first number in successive pair increases by 4 then 8 then 16 then 32. The second number in a pair increases by 8 then 16 then 32.
8
62
The pattern is +4, 2x, +4, 2x, and so on. The next number is 32.
twenty five
17?
18
Not sure about "completing" the pattern since there following is the solution from an infinite sequence. You can fit the polynomial: t(n) = (-45n6 + 993n5 - 8385n4 + 33895n3 - 66930n2 + 59192n - 15360)/240 with n = 1, 2, 3, ... and the next term will be -308.
The 2 numbers in a row are multiplied, then you subtract one and that's the next number in the sequence. EG, 2x2 = 4 4-1=3 2x3=6 6-1=5 3x5=15 15-1=14 number sequence is 2, 2, 3, 5, 14
77-49=28÷2=〔14〕 21+14=35 35+14=49 49+14=63 63+14=77
8
62
25 is odd
14
8
The pattern is +4, 2x, +4, 2x, and so on. The next number is 32.
The next number has to be 41; you always add the powers of three to the previous number beginning with 0. 3^0=1; 1+1=2; 3^1=3; 2+3=5; 3^2=9; 5+9=14; 3^3=27; 14+27=41 the next number would be 122 (81+41); you could also multiply the number by 3 and then substract 1. By the way: x(n)=x(n-1)+3^(x-2) ------------------------------------------------------------------------------------------------------------------- It could also be the Catalan number sequence, found by 1/(n+1) * (2n choose n), in which case the next number would be 42.
twenty five