each pair is a double i.e. 14 and 28, 18 and 36, 26 and 52 and so on. Each successive pair is increased by double the last increase. So looking at every other number, 14+4=18 18+8=26 26+16=42 so the next pair would be 42+32=74 and its double 148
Another way to think of it is the first number in successive pair increases by 4 then 8 then 16 then 32. The second number in a pair increases by 8 then 16 then 32.
To determine the pattern in the series 17, 20, 14, -1, we can see that the difference between each consecutive number is not consistent. The sequence seems to be alternating between adding and subtracting numbers. Specifically, the pattern is +3, -6, -15. Following this pattern, the next number in the series would be obtained by subtracting 24 from -1, resulting in -25.
8
62
17?
twenty five
18
Not sure about "completing" the pattern since there following is the solution from an infinite sequence. You can fit the polynomial: t(n) = (-45n6 + 993n5 - 8385n4 + 33895n3 - 66930n2 + 59192n - 15360)/240 with n = 1, 2, 3, ... and the next term will be -308.
To determine the pattern in the series 17, 20, 14, -1, we can see that the difference between each consecutive number is not consistent. The sequence seems to be alternating between adding and subtracting numbers. Specifically, the pattern is +3, -6, -15. Following this pattern, the next number in the series would be obtained by subtracting 24 from -1, resulting in -25.
The 2 numbers in a row are multiplied, then you subtract one and that's the next number in the sequence. EG, 2x2 = 4 4-1=3 2x3=6 6-1=5 3x5=15 15-1=14 number sequence is 2, 2, 3, 5, 14
62
8
25 is odd
77-49=28÷2=〔14〕 21+14=35 35+14=49 49+14=63 63+14=77
The pattern appears to be: subtract 6, add 17, subtract 14, add 9, subtract 7. Following this pattern, the next number should be obtained by adding 3 to the last number in the sequence, which is 6. Therefore, the next number in the sequence is 9.
8
14
The next number has to be 41; you always add the powers of three to the previous number beginning with 0. 3^0=1; 1+1=2; 3^1=3; 2+3=5; 3^2=9; 5+9=14; 3^3=27; 14+27=41 the next number would be 122 (81+41); you could also multiply the number by 3 and then substract 1. By the way: x(n)=x(n-1)+3^(x-2) ------------------------------------------------------------------------------------------------------------------- It could also be the Catalan number sequence, found by 1/(n+1) * (2n choose n), in which case the next number would be 42.