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1. Divide number by 2, record the remainder. Repeat until you reach 0.

2. Re-write the remainders from bottom to top.

3. Check

TEST -> ANS -> R

57/2 -> 28 -> 1

28/2 -> 14 -> 0

14/2 -> 07 -> 0

07/2 -> 03 -> 1

03/2 -> 01 -> 1

01/2 -> 00 -> 1

57 dec = 111001 bin

Check:

[1] [1] [1] [0] [0] [1]

(1*25)+(1*24)+(1*23)+(0*22)+(0*21) +(1*20)

32 + 16 + 8 + 0 + 0 + 1

= 57

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Q: How do you convert 57 into binary?
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