MMSCFD to LB per HR 1909.8 HR LB 520 R 1 1545.33FT - LB LB R 24HR DAY LB (.6 29)LB MMSCF 1,000,000SCF DAY 1.0MMSCF FT 144IN IN 14.7LB HR LB O O MOL MOL 2 2 2 = × − × × × = × × × × This equation shows the conversion from MMSCFD to LB per HOUR.
That depends what you want to convert it to. Divide it by 60 to convert to hours. Divide the result by 24 to convert to days. Divide the result by 365 to convert to years.That depends what you want to convert it to. Divide it by 60 to convert to hours. Divide the result by 24 to convert to days. Divide the result by 365 to convert to years.That depends what you want to convert it to. Divide it by 60 to convert to hours. Divide the result by 24 to convert to days. Divide the result by 365 to convert to years.That depends what you want to convert it to. Divide it by 60 to convert to hours. Divide the result by 24 to convert to days. Divide the result by 365 to convert to years.
Use VMWare convert to convert it to a vmware workstation file, then ovf tool to convert to ovf.
That depends what you want to convert it to. To convert to square feet, divide by 144.That depends what you want to convert it to. To convert to square feet, divide by 144.That depends what you want to convert it to. To convert to square feet, divide by 144.That depends what you want to convert it to. To convert to square feet, divide by 144.
That depends what you want to convert it to.That depends what you want to convert it to.That depends what you want to convert it to.That depends what you want to convert it to.
There is a standard formula to convert from MMBTu to SM3. Multiply the mmbtu number by 26.37 to get the SM3 number.
Let me know Heating value.
It is not clear what sm3 stands for but, in all likelihood, there is no valid conversion because the dimensions of the units are different.
The conversion can be done simply by first converting MMSCFD into M3D i.e converting Millions of Standard Cubic Feet per Day(MMSCFD) into Standard Cubic meter per day (M3D) 1 MMSCFD = 28316.847 M3D = 1179.869 M3h (however this is for a standard temp of 60oF)
Witohut knowing the density of your material, you can't.
MMSCFD to LB per HR 1909.8 HR LB 520 R 1 1545.33FT - LB LB R 24HR DAY LB (.6 29)LB MMSCF 1,000,000SCF DAY 1.0MMSCF FT 144IN IN 14.7LB HR LB O O MOL MOL 2 2 2 = × − × × × = × × × × This equation shows the conversion from MMSCFD to LB per HOUR.
Coverting MMSCFD which is million standard cubic feet per day to CFM or cubic feet per minute requires knowing how many minutes are in a day. This can be determined by multiplying 60 by 24 and then dividing the MMSCFD by this product.
MMSCFD =Millions of standard cubic feet per day. Usually used for volumetric flow rate for gases. to convert MMSCFD to cubic metre per day (m3/day), multiply by 28316.847 but this is only if the flow is calculated at a standard temp. of 60 o F other wise it is to be modified at diffrerent temperature as per simple gas laws Vinod Kumar, SAIL Pipe line Maint. Engineer
$14,000,000,000 < sorry dude :(
One has "N" and the other had "S".
What is the population of Sutton
//Write a C program to print the sum of a sparse matrix.(Data Structure) #include #include int i,j,k,l,m,m1,m2,n1,n2,nz1=0,nz2=0,z1=0,z2=0,sm1[3][50],sm2[3][50], a[100][100],b[100][100],sm3[3][50]; void main() { clrscr(); printf("\n\n\n\t\t FIRST MATRIX"); printf("\n\nENTER THE VALUE FOR ROW = "); scanf("%d",&m1); printf("\n\nENTER THE VALUE FOR COLUMN= "); scanf("%d",&n1); clrscr(); printf("\n\nENTER THE VALUE FOR (%d*%d) MATRIX= ",m1,n1); for(i=0;inz1) printf("\n\n\nIT CAN CONVERT INTO SPARSE MATRIX\n"); else { printf("\n\nCAN'T CONVERT INTO SPARSE MATRIX\n"); exit(1); } //converting into sparse matrix printf("\n\nCONVERSION OF SPARSE MATRIX\n\n"); sm1[0][0]=m1; sm1[0][1]=n1; sm1[0][2]=nz1; k=1; for(i=0;inz2) printf("\n\n\nIT CAN CONVERT INTO SPARSE MATRIX\n"); else { printf("\n\nCAN'T CONVERT INTO SPARSE MATRIX\n"); exit(1); } //converting into sparse matrix printf("\n\nCONVERSION OF SPARSE MATRIX\n\n"); sm2[0][0]=m2; sm2[0][1]=n2; sm2[0][2]=nz2; l=1; for(i=0;i=m2&&n2) { sm3[0][0]=m1; sm3[0][1]=n1; sm3[0][2]=nz1+nz2; } else { sm3[0][0]=m2; sm3[0][1]=n2; sm3[0][2]=nz1+nz2; } k=1,l=1,m=1; while(nz1!=0&&nz2!=0) { if(sm1[k][0]==sm2[l][0]&&sm1[k][1]==sm2[l][1]) { sm3[k][0]=sm1[k][0]; sm3[k][1]=sm1[k][1]; sm3[k][2]=sm1[k][2]+sm2[k][2]; k++; l++; m++; nz1++; nz2++; } //printing of addition OS sparse matrix printf("\n\n\t\tADDTION OF SPARSE MATRIX IS\n\n"); for(i=0;i