If I've read your question correctly, you need to subtract: a2 +2a -7 a2 -4a2 +5a2 -6 = 2a2 -6 Note, if x - y = z, then y = x - z; so: 2a2 -6 - (a2 -2a +1) = 2a2 -6 - a2 +2a -1 = a2 +2a -7
2a2+3a2 = 5a2
3a4 - 2a2 + 5a - 10 - 2a4 + 4a2 + 5a - 2 = a4 + 2a2 + 10a - 12 = a4 + (2a - 2)(a + 6)
2a+6b
2a
a(2a + 1)
(2a-3)(a-1)
(a - 1)(2a - 3)
a2(2a2-21a+49) a2(2a-7)(a-7)
2a2 - 13a + 15 = (2a - 3) (a - 5)
(a2 + a + a2) = (2a2 + a) = a (2a + 1)
6a to the second power minus 8ab + 2a
If I've read your question correctly, you need to subtract: a2 +2a -7 a2 -4a2 +5a2 -6 = 2a2 -6 Note, if x - y = z, then y = x - z; so: 2a2 -6 - (a2 -2a +1) = 2a2 -6 - a2 +2a -1 = a2 +2a -7
2a2+3a2 = 5a2
8
3a4 - 2a2 + 5a - 10 - 2a4 + 4a2 + 5a - 2 = a4 + 2a2 + 10a - 12 = a4 + (2a - 2)(a + 6)
2a-5