[ x8 - 5x2 ] is not the difference of two squares. [ 5x2 ] is not really a square.
If you do have the difference of two squares, then:
-- Take the square roots of the two terms.
-- The factored form is (sum of the square roots) times (difference of the square roots)
Example:
Let's use . . . [ x8 - 9x2 ] .
The square roots of the terms are . . . [ x4 ] and [ 3x ] .
The factored form is (x4 + 3x) (x4- 3x).
Go ahead and FOIL those factors out and you'll see.
With this particular example, you could also continue, and
factor 'x' out of each of these factors, to wind up with
x2 (x3 + 3) (x3 - 3)
-7
x2 + 36 cannot be factored. You can only factor the difference of two squares, not the sum.
100a2 - 49b2 is the difference of two perfect squares. Therefore, it is equal to the sum times the difference of the roots: (10a + 7b)(10a - 7b)
Difference
Let a represent the scale factor of the two squares. Then it follows that the ratio of the areas is a^2. If these are equal, you get the equation a = a^2, and this is only true for a=0 or a=1. However, the only applicable value for a here is 1. In short, yes, they can, but only if both the scale factor and the ratio of the areas are equal to 1 (i.e. the squares are congruent)
There is a formula for the difference of two squares. The sum of two squares doesn't factor.
The formula to factor the difference of two squares, a2 - b2, is (a + b)(a - b).
It is the difference of two squares which is: (x+2y)(x-2y)
use the difference of two squares yule.
(x + 3)(x - 3)
a^2 - b^2 = (a + b)(a - b)
It is the difference of two squares which is: (6-10w)(6+10w)
This expression is the difference of squares. It can be factored to (9 - 7n4)(9 + 7n4)
-7
x2 + 36 cannot be factored. You can only factor the difference of two squares, not the sum.
factoring whole numbers,factoring out the greatest common factor,factoring trinomials,factoring the difference of two squares,factoring the sum or difference of two cubes,factoring by grouping.
a^2 - b^2 = (a - b)(a + b) a^2 + b^2 doesn't factor rationally.