x3 + 4x2 + 16x + 64
=x2*(x + 4) + 16(x + 4) = (x + 4)*(x2 + 16) which has no further real factors.
You don't. There is no way to factorise it.
16X + 12X all I can see here is factoring out a 4X factor 4X(4 + 3) ---------------
Half of the coefficient of x, squared. For example: x2 + 16x -3 you would add 8^2. Then you would have: x2 +16x +8^2 = 3-8^2 Which leads to: (x+8)^2 = -61
16x + 3
If your function is 4x^2+16x+16=0 then x=-2, if it is 4x^2-16x+16=0, then x=2
4x(4x^2 + 3x + 1)
x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).
No solution in integers.
(3x + 1)(x + 5)
(x + 5)(3x + 1)
2(x - 7)(x - 1)
It is 16x squared plus 80x plus 100.Very complicated!
2x2+14x
4x times 4x equals 16x2.
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
4x^2 = 16x 16x - 60x = -44x -44x + 225
x2 + 16x - 348 cannot be factored. Solving for x with the quadratic formula results in x = -8 - 2√103 and x = -8 + 2√103