a=64 b=8 (x+16x+64)=(x+8)^2
2x^3-3x^2-11x+7x+32x^2-9x+16 R -41x+3 l 2x^3-3x^2-11x+7-(2x^3+6x^2)-9x^2-11x+7-(-9x^2-27x)16x+7-(16x+48)-412x^2-9x+16-[41/(x+3)]
x2-1=(x-1)(x+1)It factors out like this because it's the difference of two squares. It only works with subtraction and is always in the format with two groups of parenthases. For example: 16x-4. 16 and 4 are both squares, so it factors out like this: (4x+2)(4x-2). One set is always minus, the other is always plus. The order doesn't matter.
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
x+15=16x=16-15x=1
x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).
4x^2 = 16x 16x - 60x = -44x -44x + 225
No solution in integers.
(3x + 1)(x + 5)
(x + 5)(3x + 1)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: -8 plus or minus 4 times the square root of 30. x = 13.908902300206645 x = -29.908902300206645
x2 + 16x - 348 cannot be factored. Solving for x with the quadratic formula results in x = -8 - 2√103 and x = -8 + 2√103
That won't factor neatly, so we apply the quadratic formula. x = -8 plus or minus 2 times the square root of 5 x = -3.5278640450004204 x = -12.47213595499958
4x(4x^2 + 3x + 1)
It is: x2-16x+60 = (x-6)(x-10) when factored
5x2-16x+12 = (5x-6)(x-2) when factored with the help of the quadratic equation formula
It is 16x squared plus 80x plus 100.Very complicated!