It is 3(2y+3) when factorized
3x2 + 22x + 7 = 3x2 +21x + x + 7 = 3x(x + 7) + (x + 7) = (x + 7)(3x + 1)
42
5x + 5y = 5(x+y)
-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3
8
-2(x + 5)(x - 6)
444+444+444+444=22x 1776=22x x80.73
2x + 3mn - 33n + 22x = 24x + 3m(n - 11)
If 22x = 132,x = 132/22 = 6
It is a quadratic equation and the values of x are: -1/2 and 6
x2 - 22x + 121 = (x - 11)2
22x
4x
Not if x is an integer.
121
Two factors of 6 that add to -5? Try -2 & -3... (x - 2)(x - 3)