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91 92 93 94 95
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JudyLet the number be represented by 'a'
a+(a+1)+(a+2)+(a+3)+(a+4)=465
a+a+1+a+2+a+3+a+4=465
a+a+a+a+a+1+2+3+4=465
5a+10=465
5a=465-10
5a=455
5a/5=455/5
a=91
So if a=91
a+1=92
a+2=93
a+3=94
a+4=95
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First 10-digit prime found in consecutive digits of c?
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695
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