60, 62, 64, 66, 68
60.
The numbers are 21, 22, 23, 24, and 25.
Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4. Add n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115 5n + 10 = 115 5n = 105 n = 21 N+1 = 22 n+2 = 23 n+3 = 24 n + 4 = 25 So the five consecutive numbers are 21,22,23,24 & 25.
12, 13, 14, 15, 16
5872345098234783904672083946728390752430689723409687298290843 theres your answer
60.
60,62,64,66,68
The value of the greatest integer is 76. This occurs when the set of five consecutive integers is all even numbers.
The numbers are 16, 18, 20, 22 and 24.
-4, -2, 0, 2, 4
741,743,745,747,749
4+5+6+7+8 = 30
8 10 12 14 16
15,17,19,21,23
To find five consecutive numbers that sum to 320, you can set up the equation where the middle number is ( x ). The five numbers would then be ( x - 2, x - 1, x, x + 1, x + 2 ). Their sum can be expressed as ( (x - 2) + (x - 1) + x + (x + 1) + (x + 2) = 5x ). Setting this equal to 320 gives ( 5x = 320 ), so ( x = 64 ). Therefore, the five consecutive numbers are 62, 63, 64, 65, and 66.
The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.
The five consecutive even integers starting with -6 are -6, -4, -2, 0, and 2. Each number increases by 2 from the previous one, maintaining the even integer property. This sequence illustrates a simple arithmetic progression of even numbers.