If this is in the context of finding a root of an equation, the answer is to make some guesses. Find value x1 and x2 such that f(x1) and f(x2) have opposite signs. Then, provided that f is a continuous function over (x1, x2), the bisection method will find its root.
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I'm not familiar with the "bisection method" to find the roots of 2x2-5x+1 = 0 but by completing the square or using the quadratic equation formula you'll find that the solution is: x = (5 + or - the square root of 17) over 4 Hope that helps.
Range = Maximum - Minimum
∠PQR Where PQR form an angle and Q is the angle's vertex. The bisection is the line that goes between the lines QP and QR Bisection is a mathematical tool to find the root of intervals. Example: ∠PQR Form an angle of 75° A bisection would lead into two smaller angles which can be called ∠PQA and ∠RQA, both 37,5° And then you can do calculations on the smaller angles, depending on what root you are looking for.
Subtract them. The range is 4.
the domain is when the denominator of the problem is set to zero... but i am not sure how to find the range