To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
-15m but -15 metres doesnt exist
5m+3=3m+9 5m+3-3=3m+9-3 5m=3m+6 5m-3m=3m+6-3m 2m=6 (2m)/2=6/2 m=3
-3m = 5m+8 -3m-5m = 8 -8m = 8 m = -1
4m+9+5m-12=42 9m=45 m=5
The perimeter of a triangle is the sum of its three sides. If two are 3m and 2m then their sum is 3m + 2m = 5m And the remaining side can be calculated by taking this sum from the perimeter → the other side is 9m - 5m = 4m long.
5m,4m,3m respectively
5*4*3 60?
-15m but -15 metres doesnt exist
The area of rectangle is : 20.0
Oh, dude, you're hitting me with some math lingo! So, if a rectangle has dimensions 5m by 3m, its perimeter would be 16m (2x5 + 2x3). To find another rectangle with the same perimeter, you could have dimensions like 4m by 4m (2x4 + 2x4 = 16m). It's all about balancing those sides, like a seesaw, man.
-7m - 3m + 5m = -5m
5m+3=3m+9 5m+3-3=3m+9-3 5m=3m+6 5m-3m=3m+6-3m 2m=6 (2m)/2=6/2 m=3
Rectangles are really simple. The perimeter is twice the length plus twice the width (in this case 4m x 2 = 8m, 5m x 2 = 10m, and 8m + 10m = 18m). The area is simply the length times the width (in this case, 4m x 5m = 20m2).
Every one of them could be a side of a rectangle. It is not possible to give an answer in respect of an unspecified rectangular object. however, i feel the question is incorrect as it should be sides of the triangle and according to it 3rd is the answer as 3+5<9 :)
The area is 15 square metres.
-3m = 5m+8 -3m-5m = 8 -8m = 8 m = -1
The pressure exerted by the body is calculated by dividing the force by the area. In this case, the pressure would be 450N / (5m x 4m) = 22.5 Pascal.