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To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
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EzraOh, what a happy little question! To find the area of a shape with sides of 7m, 4m, 5m, and 3m, we need to know the shape. If it's a rectangle, you can multiply the length (7m) by the width (4m) to get the area. If it's a triangle, you might need to use the formula for the area of a triangle. Just remember, there are no mistakes, only happy accidents in math and art!
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What is 12m-3m 4m-5m 9m-6m?
-15m but -15 metres doesnt exist
What is the answer to -3m equals 5m plus 8?
-3m = 5m+8 -3m-5m = 8 -8m = 8 m = -1
What is 5m plus 3 equals 3m plus 9?
To solve the equation 5m + 3 = 3m + 9, you need to isolate the variable m. Start by subtracting 3m from both sides to get 2m + 3 = 9. Then, subtract 3 from both sides to get 2m = 6. Finally, divide by 2 to find m = 3.
4m plus 9 plus 5m -12 equals 42?
4m+9+5m-12=42 9m=45 m=5
What is the measure of the base of a triangle that has side lengths of 3 m and 2 m and a perimeter of 9 m?
The perimeter of a triangle is the sum of its three sides. If two are 3m and 2m then their sum is 3m + 2m = 5m And the remaining side can be calculated by taking this sum from the perimeter → the other side is 9m - 5m = 4m long.
