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How do you find the center and semi-major and semi-minor axis for ellipse with equation 16x2 plus y2 equals 16?
Wiki User
∙ 14y ago
An ellipse with centre (xo, yo) with major and minor axes a and b (the larger of a, b being the major axis) has an equation of the form:
(x - xo)2 / a2 + (y - yo)2 / b2 = 1
The semi-major and semi-minor axes are half the major and minor axes.
So re-arrange the equation into this form:
16x2 + y2 = 16
x2 + y2 / 16 = 1
(x - 0)2 / 12 + (y - 0)2 / 42 = 1
Giving:
Centre = (0, 0)
Major axis = 2
Semi-major axis = 2/2 = 1
Minor axis = 1
Semi-minor axis = 1/2
Wiki User
∙ 14y ago
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