There is more than one way, but the idea of a factor tree is an easy way to do it. Start with 36 itself. A number is always a factor of itself since 36x1=36. Now since you know 36 is even, divide it by 2 and you have 18. See how it did it below and continue dividing. 36=18x2=9x2x2=3x3x2x2=3x3x2x2x1 So looking at the above we have The first thing after the 36 is 18 and 2 so those are two factors. I will use[ ] for my factor list. [Factor list]=[18,2] Next we have 9x2x2 so 9 and 9x2 are factors. [ 18,2,9] Now we have 3 ( we have 9 too, but I already have it) and we have 3x2=6 and 2x2x3=12 [18,2,9,3,6 12] Now we have 1 also [1,2,3,6,9,12,18,36]
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Square numbers have an odd number of factors. Ignoring the square root, half of the remaining factors will be less than the square root, half will be more. The square root of 36 is 6. Test 1 through 5. 1 is, 2 is, 3 is, 4 is, 5 is not. Divide 1 through 4 into 36.
1, 2, 3, 4, 6, 9, 12, 18, 36
The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. To determine which factors are perfect squares, we need to find the square root of each factor. The factors that have whole number square roots are perfect squares. In this case, the perfect squares among the factors of 36 are 1, 4, 9, and 36.
60
36 has 9 factors including 1 and 36. Its factors are: 1, 2, 3, 4, 6, 9, 12, 18, 36.
The common factors of 18 and 36 are 18,9,6,3,2,1.
The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. To find which factors are multiples of 6, we need to see which numbers can be evenly divided by 6. In this case, the multiples of 6 among the factors of 36 are 6, 12, 18, and 36. These numbers can be divided by 6 without leaving a remainder.