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Q: How do you find the perimeter of the rectangle whose length is 40cm and a diagnol is 41cm?

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You forgot to put in the length of the rectangle's perimeter.

56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56

360

6 feet

Perimeter = 5+5+3.5+3.5 = 17 feet

If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.

I think you mean the width is 6. The answer depends entirely on what the length of the rectangle is. For example, if it is a square, so that the length and width are both 6, the answer is 24. I the length is 10, the perimeter is 32. In general, just add the width (6) to the length and double the sum to get the perimeter.

Perimeter = 2*(Length + Width) = 2*(24.6 + 12.2) = 2*36.8 = 73.6 units

that's easy.....it's 1 ;)

Length + width = half of perimeter ie 36.7 in. If length is 4.7 in then width is 32 in.

The perimeter of a rectangle is equal to twice the length plus twice the width, so P = 2l + 2w P = (2x25) + (2x13) P = 50 + 26 P = 76 centimeters

Perimeter equals the sum of all sides. Therefore 7+7+6+6=26

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