For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex).
Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
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A perpendicular bisector is a straight line that divides a side of a triangle in two and is at right angles to that side. An angle bisector is a straight line that divides an angle of a triangle in two.
thank goodness for my math teacher, norm! he said only in an isosceles triangle. The bisector of the vertex angle of an isosceles triangle is perpendicular to the base! =)
Find the midpoint of a side and join it to the vertex opposite. That is a median and it divides the mass of a triangle in two halves. Each triangle has three medians. However, there is no reason for a bisector to go through a vertex - it can be a straight line through any point in the triangle. In such a case drawing the bisector analytically is likely to be beyond the skills of most geometry students. There is, though, a very simple practical solution. Cut out a copy of the triangle on a uniform lamina. Suspend it vertically by a pin through the required point. Then the vertical line through that point (use a plumb line) is the bisector of the triangle through that point.
If you perform an angle bisector on an angle in a triangle, then it will go through the midpoint of the opposite side.
A right bisector of a line segment, is better know as a perpendicular bisector. It is a line that divides the original line in half and is perpendicular to it (makes a right angle).