Find the difference of it which is 3, so 3n-1
One rule for this pattern is to add twice the previous value added 4 + 1 = 5 5 + 2×1 = 5 + 2 = 7 7 + 2×2 = 7 + 4 = 11 11 + 2×4 = 11 + 8 = 19 Continuing the next numbers would be: 19 + 2×8 = 19 + 16 = 35 35 + 2×16 = 35 + 32 = 67 ...
It is not a rule as such; those number are the first 10 prime numbers.
(2, -5)
57 ÷ 11 = 5 remainder 2 or: 57 ÷ 11 = 5 2/11 = 5.181818... ≈ 5.182
-31. The rule is t(n) = -2n3 + 12n2 -19n + 14 where n = 1, 2, 3, ...
prime numbers
you multiply them together 11*25=275. * * * * * For multiplication by 11, I would do 2 5 / \ / \ 2 2 + 5 5 = 2 7 5 ie 275
One rule for this pattern is to add twice the previous value added 4 + 1 = 5 5 + 2×1 = 5 + 2 = 7 7 + 2×2 = 7 + 4 = 11 11 + 2×4 = 11 + 8 = 19 Continuing the next numbers would be: 19 + 2×8 = 19 + 16 = 35 35 + 2×16 = 35 + 32 = 67 ...
The rule is t(n) = 5 + 2*n, where n = 1, 2, 3, ...
1 2 3 4 5 2 5 8 11 14 ... If this is the sequence, the position-to-term rule is 3n-1. However, it could be another sequence depending on the rest of the terms.
Add 5 to form the next number in the sequence, then subtract 2 . . . repeat. 0 + 5 = 5 5 - 2 = 3 3 + 5 = 8 8 - 2 = 6 . . . and the series continues :- 6 + 5 = 11 11 - 2 = 9 . . . and so on
The difference doubles each time. 2+3=5.. 5+6=11.. 11+12=23..Therefore the next number in the sequence would be 47, since 23+24 = 47.
t(n) = 5 + 2*n
Find the prime factors of the two numbers: 44 = 2*2*11 110 = 2*5*11 Then find ones that appear in both factorisations: 2 and 11. Multiply them together so GCF = 2*11 = 22
The Girl's Guide to Depravity - 2012 The 'Get Under Another' Rule 2-5 was released on: USA: 2013 USA: 11 October 2013
Prime factors of 55 are: 5 and 11 Prime factors of 70 are: 2, 5 and 7 LCM is: 2*5*7*11 = 770
If you mean: 2 5 11 23 47 then they are increasing by 3 6 12 24