The answer will depend on what r is meant to be. And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
One-eighth of a quantity ( r ) can be calculated by dividing ( r ) by 8. Mathematically, it can be represented as ( \frac{r}{8} ). This means that if you have a value for ( r ), you can find one-eighth of that value by simply dividing it by 8.
The U value is the inverse of the R value. For R value 19 insulation the U value is 1/19, or 0.0526.
For the question to have any meaning, the volume should be in cubic metres, not metres. The surface area of a sphere of radius r is 4*pi*r*r and its volume is 4/3*pi*r*r*r. Use the second equation to find the value of the radius, r and then use that value in the first equation to calculate the surface area.
The formula for the area of a circle is r*r*pi, where r is radius. Radius is half of the diameter, so to find the area you first need to find half of 17. 17/2=8.5 Then put that in the formula to find the answer. 8.5*8.5*3.14=226.865 with a more accurate value for Pi you get 226.98
"r" you kidding?
There is only one geostationary orbit because in order for any mass m to orbit the Earth (ME) the gravitational force: EQ1: Fg = GmME/r^2 has to be such that it is equal to the required centripetal force for uniform circular motion: EQ2: Fc = mv^2/r where v is the velocity of m at radius r (distance from the center of the Earth) and: EQ3: v = 2(pi)(r)(f) f is the frequency of rotation in revolutions per second. For geostationary orbit the satellite must be in a fixed position (it must have the same frequency of rotation or angular velocity as the Earth's rotation) relative to the Earth and orbit above the Earth's equator. The necessary velocity to satisfy Fg = Fc is a specific value, therefore (since pi and f are fixed values) r is the only variable in EQ3. There is a specific orbital radius for geostationary orbit of any mass m.
Distance= (r - R)/1000 Reference= http://lennyconundrumsolutions.blogspot.com/2008/07/round-271.html r= the distance between the Neopia's center of mass to the Kreludor moon's geostationary orbit (unsure of actual value) R= d/2 = 800 km = 800,000 m (radius) We use 1000 factor in the above equation because we want to get in kilometers. Round that distance number and we get the answer.
The formula to find the orbital speed v for a satellite in a circular orbit of radius r is v (G M / r), where G is the gravitational constant, M is the mass of the central body, and r is the radius of the orbit.
One-eighth of a quantity ( r ) can be calculated by dividing ( r ) by 8. Mathematically, it can be represented as ( \frac{r}{8} ). This means that if you have a value for ( r ), you can find one-eighth of that value by simply dividing it by 8.
C=2(pi)r, so C=(2)(3.14)r
The area of a circle with radius r is pi*r*r and its circumference is 2*pi*r Use the first to find r and then use that value of r in the second to find the circumference.
20-50 or so
Lenght x r x pie x 2
Lenght x r x pie x 2
I am wanting to build a hearth for a wood stove using natural river rock. But can't find the R-value for river rock. can anyone help?
The U value is the inverse of the R value. For R value 19 insulation the U value is 1/19, or 0.0526.
(Assuming sattelite mass is small enough compared to that of earth so it can beignored in the calculations)Basically, the nearer you are, the faster you have to go.CALCULATING ORBITAL VELOCITY (v) (radius given)G = newtons gravitational constant (6.673 * 10-11)M = mass of earth ( 5.974 * 1024 kg)r = orbital radiusv = orbital velocityFor any given orbital radius, only one velocity will sustain stable orbit.(Acceleration due to gravity) = (Acceleration due to centripetal force)(G*M / r2) = (v2 / r)For stable orbit velocity, first choose orbital radius.Rearrange (G*M / r2) = (v2 / r) to isolate v (stable orbit velocity)v = square root ( (G* M) / rExample:The minimum altitude where you will be free of atmosphere gases, and thus air resistance is about 100 km (100 000 metres), from earths centre thats= 6 471 000 metresThe velocity required to produce stable orbit = square root ((G*M) / r)= 7849 metres per second (17 558 mph)Orbital time = ((2*pi*r) / v) secondsGEOSYNCHRONOUS ORBITA 360 degree rotation of the earth ( sidereal day ) takes 23.934 hours( 86164 seconds), for geostationary orbit only one orbital radius is suitable that will result in equalling this time.by trial and eror:example radius (r), calculate v, then: time (seconds) = (2*pi*r) / vrepeat until time = 86164 secondsworks out at approx 42 164 000 metres radius