if you want to find the zero/null /x-intercept of any given function you have to find the x that makes it zero. therefore if
f(x) = 2x +4
you have to put
f(x) = 0
0 = 2x +4
2x = -4
x=-2
if you subsitute -2 for x you will find that the function f(x) will equal zero
f(x)= 2 * (-2) +4
f(x) = -4 +4
f(x) = 0
if you have more complex functions like squared your approach will look something like this
say g(x) is a function of x²
g(x)=(x-2)² +4
set g(x)= 0
0= (x-2)² -4
4= (x-2) ²
+ or - radical (4) = x -2
2 + radical (4) = x or 2 -radical (4) = x
x=4 or x = 0
remember radicals always have two solutions
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If the function is in this form: y = mx + b Then b is the y-intercept. For example if the function is y = 2x + 4 then the y-intercept is 4.
In the slope-intercept form you use the slope of the line and the y-intercept to the origin has a y-intersect of zero, b = 0, and represents a direct variation. All functions that can be written on the form f(x) = mx + b belong to the family of linear function.
-8
because right away you can tell the slope and y-intercept
It cuts through the x axis and it is an extension of the line cutting through the y axis which is the y intercept