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To get 31 using the numbers 1, 2, 6, and 7, you can use the following equation: (6 * 2) + 7 + 1 = 31. This equation follows the order of operations (multiplication before addition) to reach the desired result. By multiplying 6 and 2 first, then adding 7, and finally adding 1, you can achieve the target number of 31.
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What is the answer to 7 plus 24 divided 6x2 equal too?
It depends on how you do it. 1) ((7+24)/6)*2 7+24 = 31 31/6=5.166666667 5.166666667*2=10.333333333 2) 7+((24/6)*2) 24/6=4 4*2=8 8+7=15 3) (7+24) / (6*2) 7+24=31 6*2= 12 31/12= 2.583333333 The normal way would be method (2) which follows the rule of first dividing then multiplying then adding. However when writing out a sum to do it is important to use brackets to make the order in which mathematical operations are to be performed clear because, as you can see, it does affect the result.
How 1 5 6 7 equals 21?
The answer is 6 / (1-5/7). 1- 5/7 = 2/7 6 / (2/7) = 6 * (7/2) = (6*7)/2 = 42/2 = 21. Simples!
2 2 6 2 14 2 30 2 missing number here 2?
62 because... 6+1=7 7x2=14 14+1=15 15x2=30 30+1=31 31x2=62
What is the nth term of 1 7 17 31 49?
2n^2-1
How many times does 5 go into 31?
31 ÷ 5 = 6 with remainder 1
