1p , 50p , 2p , 10p , 20p .5p
50p+20p+10p+5p+2p+1p =88p
There are 201 ways.
Oh, what a happy little question! You can make one pound using different combinations of coins. You can use 100 one-penny coins, or 50 two-penny coins, or 20 five-penny coins, or 10 ten-penny coins, or 5 twenty-penny coins, or 2 fifty-penny coins. Just mix and match those coins and let your creativity shine!
how many ways to make 25p using 1p 2p 5p 10p 20 coins
1p , 50p , 2p , 10p , 20p .5p
50p+20p+10p+5p+2p+1p =88p
There are 201 ways.
8 Coins of the Realm - a reference to the coins of the UK. 1p 2p 5p 10p 20p 50p £1 £2
Oh, what a happy little question! You can make one pound using different combinations of coins. You can use 100 one-penny coins, or 50 two-penny coins, or 20 five-penny coins, or 10 ten-penny coins, or 5 twenty-penny coins, or 2 fifty-penny coins. Just mix and match those coins and let your creativity shine!
40 ways.
England's currency is the pound. A pound is made up of 100 pennies. There are coins of different amounts:1p,2p,5p,10p,20p,50p,£1, and £2.
There are many possible answers and these will depend on the country and currency. For example, for the UK, one possible answer is 1 * 50p 3 * 20p 17 * 10p 9 * 1p
how many ways to make 25p using 1p 2p 5p 10p 20 coins
If you mean the currency denominations... 1p (penny), 2p, 5p, 10p, 20p, 50p, £1 & £2 coins - £5, £10, £20 & £50 notes.
In the 1950s people had pounds, shillings, pence and half pence. Now we have pounds, notes, 2 pound coins, 50p, 20p, 10p, 5p, 2p and 1p. Alot has changed!
To find the number of ways to make 50p using the given coins, we can use a technique called dynamic programming. We can create an array of size 51 to store the number of ways to make each value from 0 to 50p. We initialize the first element as 1 (since there is one way to make 0p), and then iterate through each coin denomination, updating the array based on the current coin value. Finally, the value at index 50 of the array will give us the total number of ways to make 50p using the given coins.