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ax2+bx+c=0
Multiply the whole equation by 4a:
4a2x2+4abx+4ac=0
Move the 4ac to the other side:
4a2b2+4abx=-4ac
Add b2 to both sides:
4a2b2+4abx+b2=b2-4ac
The left side of the equation is like (a+b)2=a2+2ab+b2, with a being 2ab and b being b:
(2ax+b)2=b2-4ac
Do a square root on both sides of the equation:
2ax+b=√(b2-4ac)
Move the b to the other side of the equation:
2ax=-b±√(b2-4ac)
Leave only x on the left side of the equation by dividing the right side by 2a:
x=(-b±√(b2-4ac))/2a
The previous explanation:
aX2+bx+c is the same as x=-b (plus or minus the square root) of b2 - 4ac divided by two times a.
x=(-b±√(b^2-4ac))/2a
x can equal (-b+√(b^2-4ac))/2a ∆ (not delta) (-b-√(b^2-4ac))/2a
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What is the quadratic formula?
x = [−b ± √(b2 − 4ac)]/2aA, B, and C can all correspond to the original quadratic equation as follows: ax2 + bx + c = 0The quadratic formula can only be used if the quadratic equation is equal to zero.If [ Ax2 + Bx + C = 0 ], thenx = [ -B +/- sqrt( B2 - 4AC ) ]/ 2A
What is the example of quadratic trinomial?
[ Ax2 + Bx + C ] is one example.
What is the standard form of a quadratic function?
ax2 +bx + c = 0
What is sheree dharacharya formula?
If quadratic equation is ax2+bx+c then by shree Dharacharya formula roots of equation can be found by this formula (-b+-sqrt(b2-4ac))/2a
what is the correct quadratic formula?
The roots of the equation [ Ax2 + Bx + C = 0 ] arex = 1/2A [ -B ± sqrt(B2 - 4AC) ]
How do you write a quadratic formula?
ax2 + bx + c = y
What is the answer to yx-1squared 2 y ax2 bx c?
If you mean: ax2+bx+c = 0 then this is the formula for a quadratic equation whereas a is greater than zero
What is the formula to find the product of the roots of a quadratic equation?
If the quadratic is ax2 + bx + c = 0 then the product of the roots is c/a.
What is the quadratic formula?
x = [−b ± √(b2 − 4ac)]/2aA, B, and C can all correspond to the original quadratic equation as follows: ax2 + bx + c = 0The quadratic formula can only be used if the quadratic equation is equal to zero.If [ Ax2 + Bx + C = 0 ], thenx = [ -B +/- sqrt( B2 - 4AC ) ]/ 2A
How do you use the quadratic formula to solve a quadratic equation?
You convert the equation to the form: ax2 + bx + c = 0, replace the numeric values (a, b, c) in the quadratic formula, and calculate.
How do you find the additive inverse of a quadratic equation?
Change all the signs. Suppose you have the quadratic equation: y = ax2 + bx + c Its additive inverse is -ax2 - bx - c.
Solve this quadratic equation using the quadratic formula?
For any quadratic ax2 + bx + c = 0 we can find x by using the quadratic formulae: the quadratic formula is... [-b +- sqrt(b2 - 4(a)(c)) ] / 2a
What do quadratic equations look like?
ax2 + bx + c
How do you change a quadratic formula from standard to vertex form?
You complete the squares. y = ax2 + bx + c = (ax2 + b/2a)2 + c - b2/(4a2)
What is the name of An equation of the form ax2 bx c 0?
If you mean: ax2+bx+c = 0 then it's the general form of a quadratic equation
What is a solution of a quadratic?
A quadratic function is ax2+bx+c You can solve for x by using the quadratic formula, which, as the formula requires the use of square roots, would be tricky to put here.
What is the example of quadratic trinomial?
[ Ax2 + Bx + C ] is one example.
