Quickly check to see whether it's divisible by both 2 and 3.
Here's how to do that easily:
-- The number is divisible by 2 if it's an even number . . . the last digit is 2, 4, 6, 8, or 0.
-- The number is divisible by 3 if the sum of its digits is divisible by 3.
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No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.
138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.
if a number is divisible by 2 and 3 then its divisible by 6
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.
The product of any number and 6 would be divisible by 6.