You can't know if a general polynomial is in factored form.
It is still called a polynomial.
It is a quadratic expression and when factored it is: (7x+5)(2x-7)
Put it into two binomilals that multipy together to create the polynomial. For example: 5K(squared)-2k-7 is factored out as: (5k+1)(-7K+1)
38
You multiply the factors.
The factored form of a polynomial is valuable because it simplifies the process of finding its roots or zeros, making it easier to solve equations. It also provides insights into the polynomial's behavior, such as identifying multiplicities of roots and understanding its graph. Additionally, factored form can facilitate polynomial division and help in applications such as optimization and modeling in various fields.
It is (x+4)(x+5) when factored
The factored form of a polynomial is comprised of factors in which the sum is equal to the coefficient of the second term and the product is equal to th…
It is still called a polynomial.
15j2(j + 2)
If a number cannot be factored it is a prime number.
Completely Factored
It can, so the question does not make sense.
5x(3x+4)
a simplified polynomial is a algebraic equation/expression with variables and constants that can can be written as a sum of terms. Simplified form is the opposite of factored form P(x) = ( 2x - 3)( x+4 ) Is a factored form - product of 2 factors. Simplify P(x) by using the distributive property: P(x) = 2x2 +8x - 3x -12 P(x) = 2x2 + 5x - 12 simplified : a sum of terms!
That would be (x - 2) ( x - 5) ( x - 5). If you like, you can multiply these polynomials to get a single polynomial in standard form (i.e., not factored).
A prime polynomial is a polynomial that cannot be factored into the product of two non-constant polynomials over its coefficient field. In other words, it has no divisors other than itself and the unit (constant) polynomials. For example, in the field of real numbers, (x^2 + 1) is a prime polynomial because it cannot be factored into real linear factors. Conversely, polynomials like (x^2 - 1) are not prime because they can be factored as ((x - 1)(x + 1)).