In an ordinary electrical cell (commonly called a battery) the electrons will travel from the -ve terminal through the circuit to the +ve terminal.
[Hope I understood your question.]
Al(s) I AI3+(aq) II AI3+ (aq) I Al(s)
Multiply the ex-VAT cell by 1.2 Multiply the ex-VAT cell by 1.2 Multiply the ex-VAT cell by 1.2 Multiply the ex-VAT cell by 1.2
centrioles
A reasonable metric unit of length for a cell phone would be centimeters (cm) or millimeters (mm). Cell phones are typically measured in these units due to their small size. For example, a standard cell phone may have dimensions of around 14 cm in length and 7 cm in width. These units are more practical for measuring objects of such size compared to larger units like meters.
Scientific notation is used to express [very] large and [very] small numbers. By using scientific notation very large and very small numbers are written in a compact and easy to read form. To convert a number from standard form to scientific notation: 1) Write the number by writing the first non-zero digit followed by a decimal point 2) write the rest of the digits of the number stopping after the last non-zero digit of the number. 3) write "×10" 4) Now write a power for the 10. To work out the power count the number of digits the decimal point needs to move to get back to where it was in the original number (if there is no decimal point in the number it is "hiding" after the last digit of the number). If this movement is to the right leave it positive, otherwise if the movement is to the left make it negative. If the decimal point does not need to move, the power is 0. examples: 123000 = 1.23×10^5 0.00123 = 1.23×10^-3 1.23 = 1.23×10^0 0.0120 = 1.2×10^-2
Zn(s)/Zn2+(aq)//Au+(aq)/Au(s)
Mg(s) | Mg2+(aq)Au+(aq) | Au(s)
Mg(s) | Mg2+(aq)Au+(aq) | Au(s)
Al | Al^3+ Zn^2+ | Zn
Al(s) | Al3+(aq) Ni2+(aq) | Ni(s)
Zn(s)/Zn2+(aq)//Au+(aq)/Au(s)
Mg(s) | Mg2+(aq) Au+(aq) | Au(s)
Au(s) | Au+(aq) Al3+(aq) | Al(s)(-_^)
Zn(s)/Zn2+(aq)//Au+(aq)/Au(s)
Mg(s) | Mg2+(aq) Au+(aq) | Au(s)
Al(s) I AI3+(aq) II AI3+ (aq) I Al(s)
Type your answer here... Al(s) | Al3+(aq) Mg2+ (aq) | Mg(s)