1000 = 999 + (999 / 999)Due to the rules of BODMAS, the brackets aren't technically necessary.
Every ten there is a nine in the ones place, therefore there are 100 nines in the ones place.Every hundred there are 10 nines in the tens place, therefore add 10 * 10 nines. eg 90, 91, 92, 93, ... in the tens placeEvery thousand there are 100 nines in the hundreds place, therefore add 100 nines.Total is 300.
99/9=11
There are 1000 micrograms in a milligram. Therefore, you multiply by 1000 here. 5 milligrams is 5x1000 or 5,000 micrograms.
its impossible for 4 nines to equal 20
1000 = 999 + (999 / 999)Due to the rules of BODMAS, the brackets aren't technically necessary.
7 nines, with 5 left over.
(55 / 55) + (55 / 55) x 5 = 10
The number consists of nines, so the number will round up to 100000 as the result.
nines
It could be: 5*90 = 5
Four with a remainder of eight
Every ten there is a nine in the ones place, therefore there are 100 nines in the ones place.Every hundred there are 10 nines in the tens place, therefore add 10 * 10 nines. eg 90, 91, 92, 93, ... in the tens placeEvery thousand there are 100 nines in the hundreds place, therefore add 100 nines.Total is 300.
(5+5)x(5+5)x(5+5)=1000 and that only uses 6. If you want exactly 9 5's to equal 1000 - (5+5)x(5+5)x(5x5)+((5-5)x5)=1000
208 times,from 1 to 100 there r 11 nine such as 9 , 19 , 29, 39, 49,59, 69,79, 89, 99 its prove there are 11 nines so up to 800 there are 11*8=88 nines and from 900 to 1000 there are 100(901, 902,903......)+ 10 ( 990,991,992.....)+10(909,919,929,939....)=120 that means there are in total 88+120=208 nine in 1 to 1000
111,111,111 nines are in a billion
99 + 9(9-9)