8-6=2 or 4-2=2
(2(4 + 1) - 3)
(9 - 6)*4*2 = 3*4*2 = 12*2 = 24
13 + 7 - (6 + 4) * 2 = 0
Using four fours, you can get 19 with the following sum: 4! - 4 - (4 / 4) That is, four factorial minus four - (four divided by four) - 24 - 4 - (4 / 4) = 19
use 4 triangles, make 2 trapezoids then put them into a hexagon
(2(4 + 1) - 3)
2^2 x 3^4
You can get ten using 5,4,3,2 by the following equation: (5 x 2)(4 - 3).
4 x (1+5) = 24
2 + 2 + 2 + 2
(5-2)*4 = 12
(4! - 3)*1*2
4^2+3+1
(7 - 4) x 4 x 2 = 24
No
4/4=1 square root of 4 is 2. square root of 4 is 2. 2*2*1=4
You can use four 4's to get the result of 2 by evaluating the following: Would you like to get a result of 3 using four 4's? OK, here it is: