To make 37 using the numbers 1, 3, 5, and 7, you can use the following mathematical expression: (75) + (31) = 35 + 3 = 38. If we want to make 37 specifically, we can adjust the equation slightly by subtracting 1 from the total: (75) + (31) - 1 = 35 + 3 - 1 = 37.
1, 3, 5, 15, 37, 111, 185, 555.
15 x 1/3 = 5
5x.6.Five 5's to get 35 - 5/5 - 5/5 = 5 - 1 - 1 = 3
9+9+9+9=36-5-5-5-5=16+3+3+3-3=22+1-1-1/1=21
There are 15 of them because 15/3 = 5
You can make 37 using the numbers 1, 3, 5, and 7 by utilizing multiplication and addition. For example, you can calculate it as follows: ( (7 \times 5) + (3 \times 1) = 35 + 3 = 38 ). However, to achieve exactly 37, you need to adjust by using subtraction: ( (7 \times 5) + 1 - 3 = 35 + 1 - 3 = 33 ). This does not yield 37, indicating that it may not be possible to reach 37 using these specific numbers with standard operations.
The factors of 15 are 1, 3, 5, 15 The factors of 37 are 1, 37
1 + 2 + 3 + 4 + 5 + 6 + 7 + 2 + 3 + 4 = 37 note: there are many other variations/answers
37 ÷ 5 = 7 remainder 2 → You can make 7 teams, but have 2 children left out. However, if you meant you have a pool of 37 children and need to make a team consisting of 5 children from that 37, then how many different teams (or groups) of 5 children you can make then: This is a combination as the order of selection doesn't matter, only which 5 children are chosen. Here you can make: 37 C 5 = 37!/((37-5)!5!) = (37 × 36 × 35 × 34 × 33)/(5 × 4 × 3 × 2 × 1) = 435,897 different teams
37/5 : 6*37/6 = 37/5 : 37 = 1/5 : 1 = 1 : 5
The Greatest Common Factor (GCF) of 5, 7, and 3 is 1.
5 multiplied by 7 plus 3 minus 1
3 + 2/3 + 5 + 7/12 = 37/4 it is 37 fourths 9 and 1/4
4 multiplied by 1 3/7 is 5 5/7.
The factors of 555 are 1, 3, 5, 15, 37, 111, 185, and 555. The prime factors of 555 are 3, 5, and 37 The prime factorization of 555 is 3 x 5 x 37.
Remember BODMAS/PODMAS (or variants). 3 + 7 * 5 - 1 = 3 + 35 - 1 = 38 - 1 = 37
The factors of 555 are: 1 3 5 15 37 111 185 555 The prime factors are: 3 x 5 x 37