1, 3, 5, 15, 37, 111, 185, 555.
15 x 1/3 = 5
5x.6.Five 5's to get 35 - 5/5 - 5/5 = 5 - 1 - 1 = 3
1/5 = 0.237 divided by 0.2 = 185 times
9+9+9+9=36-5-5-5-5=16+3+3+3-3=22+1-1-1/1=21
The factors of 15 are 1, 3, 5, 15 The factors of 37 are 1, 37
1 + 2 + 3 + 4 + 5 + 6 + 7 + 2 + 3 + 4 = 37 note: there are many other variations/answers
37 ÷ 5 = 7 remainder 2 → You can make 7 teams, but have 2 children left out. However, if you meant you have a pool of 37 children and need to make a team consisting of 5 children from that 37, then how many different teams (or groups) of 5 children you can make then: This is a combination as the order of selection doesn't matter, only which 5 children are chosen. Here you can make: 37 C 5 = 37!/((37-5)!5!) = (37 × 36 × 35 × 34 × 33)/(5 × 4 × 3 × 2 × 1) = 435,897 different teams
37/5 : 6*37/6 = 37/5 : 37 = 1/5 : 1 = 1 : 5
The Greatest Common Factor (GCF) of 5, 7, and 3 is 1.
To make 37 cents with coins, you can use a combination of pennies, nickels, dimes, and quarters. The possible combinations include: 37 pennies, 1 quarter and 1 dime, 1 quarter and 3 nickels, 1 quarter, 1 dime, and 2 pennies, 3 dimes and 1 nickel, or 7 nickels and 2 pennies. In total, there are 5 ways to make 37 cents using different coin combinations.
5 multiplied by 7 plus 3 minus 1
3 + 2/3 + 5 + 7/12 = 37/4 it is 37 fourths 9 and 1/4
The factors of 555 are 1, 3, 5, 15, 37, 111, 185, and 555. The prime factors of 555 are 3, 5, and 37 The prime factorization of 555 is 3 x 5 x 37.
4 multiplied by 1 3/7 is 5 5/7.
Remember BODMAS/PODMAS (or variants). 3 + 7 * 5 - 1 = 3 + 35 - 1 = 38 - 1 = 37
The factors of 555 are: 1 3 5 15 37 111 185 555 The prime factors are: 3 x 5 x 37