77 / 7 - 7
77 / 7 - 7
77 / 7 - 7
77 / 7 - 7
If you mean: 4(2s-1) = 7s+12 then the value of s works out as 16
Puto
Expressed algebraically, this would equal 7s - 5.
7s + 12 = 131 Therefore, 7s = 119 s = 119/7 Therefore, s = 17
2
You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16
answer:4
4
If you mean: 4(2s-1) = 7s+12 then the value of s works out as 16
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
4 times with a remainder of 3
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
4/7 is in its simplest form.
To find how many times 7 fits into 31, you can divide 31 by 7. Doing the calculation, 31 ÷ 7 equals approximately 4.43. This means there are 4 whole 7s in 31, with a remainder. Thus, 31 contains four 7s.
Puto
The answer is 7s + 49.
The equivalent is 7s+2s = 9s