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To make 50 using 9 odd numbers, we can use the following numbers: 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 19 = 50. This combination adds up to 50 while using only odd numbers. The key is to select odd numbers that, when added together, equal the desired sum of 50.

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16y ago

You cannot - at least not by adding convential odd numbers. This is because adding two odd numbers always produces an even number, adding two even numbers always produces an even number, and adding an odd number to an even number always produces an odd number. So if we call all the numbers one less than the ones we're going to use by letters of the alphabet, they will all be even So if we want to use 5, we'll call 4 "A", and so on. That way % become A+1 Now, it doesn't matter what odd number we pick, they will all be of the type (B+1) + (C+1) + (D+1) + (E+1) + (F+1) + (G+1) + (H+1) + (I+1) + (J+1) there are nine even numbers and nine 1s in there and when we add them all together we will get one large even number +9, and no even number becomes 50 when 9 is added to it.

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Anonymous

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4y ago

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Q: How do you make 50 with 9 odd numbers?
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Related questions

What are the 9 odd numbers whose sum is 50 from 1 to 50?

To find the 9 odd numbers whose sum is 50 from 1 to 50, we can first calculate the sum of all odd numbers from 1 to 50, which is (50^2)/2 = 625. Next, we subtract the sum of the first 9 odd numbers (1+3+5+7+9+11+13+15+17 = 81) from the total sum, resulting in 625 - 81 = 544. Therefore, the 9 odd numbers whose sum is 50 from 1 to 50 are 19, 21, 23, 25, 27, 29, 31, 33, and 36.


What 9 odd numbers add up to 50?

An odd number of odd numbers can not add up to an even number. There fore any 9 (odd) odd numbers can not add up to 50 (even).


How do you 9 odd number 50?

Oh, dude, to find 9 odd numbers that add up to 50, you can start with 1 and keep adding 2 until you reach 17. So, 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 = 50. Easy peasy, right? Like, who needs even numbers anyway?


How first five odd numbers make 50?

(9 ÷ 3 + 7) x 1 x 5 = 50


How many horses can you tie to each pole in odd number given 50 horses and 9 poles?

The sum of 9 odd numbers will be odd and so cannot be 50.


How do you make 50 with 9 odd numbers without repeating the same number?

1 × (3 + 5 + 7 + 9 + 11 + 13 - 15 + 17) = 50.


How do you make 36 with 9 odd numbers?

You can't ! Since the product of nine odd numbers will always be an odd number !


What are the nine odd numbers that their sum can be 50?

The nine odd numbers whose sum is 50 are 1, 3, 5, 7, 9, 11, 13, 15, and 1.


How we can select five numbers single time does it take to form 50 out of this numbers 1 3 5 7 9 11 13 15 17 19?

There is no way without playing silly games. Each of the numbers in the list is odd. The sum of five odd numbers must be odd and therefore, cannot be 50. There is no way without playing silly games. Each of the numbers in the list is odd. The sum of five odd numbers must be odd and therefore, cannot be 50. There is no way without playing silly games. Each of the numbers in the list is odd. The sum of five odd numbers must be odd and therefore, cannot be 50. There is no way without playing silly games. Each of the numbers in the list is odd. The sum of five odd numbers must be odd and therefore, cannot be 50.


If you add 9 odd numbers the total should be 50 how?

1+3+5+7+9+7+9+9


Out of first 10 odd numbers 5 will make 50?

As long as more than one mathematical operator is allowed then 50 can be formed in several ways from the first ten odd numbers - i.e. those from 1 to 19. (7 x 17) - 13 - 9 - 5 = 77 - 27 = 50.


What 3 odd numbers could be added to make 50?

To find three odd numbers that add up to 50, we can set up an equation where x, y, and z are the three odd numbers. Since odd numbers are always in the form of 2n+1, where n is an integer, we can represent the three odd numbers as x=2a+1, y=2b+1, and z=2c+1. Therefore, the equation becomes (2a+1) + (2b+1) + (2c+1) = 50. Simplifying the equation, we get 2(a+b+c) + 3 = 50. Since 3 is odd, we cannot express it as the sum of three odd numbers.