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This is not going to be easy without the sigma notation, but here's the best that I can do.
Let 3 x 2 matrix A = {aij} where i = 1, 2, 3 and j = 1, 2
and 2 x 3 matrix B = {bkl} where k = 1, 2 and l = 1, 2, 3
Then their product is the matrix C = {cmn} where m 1, 2, 3 and n = 1, 2, 3 such that
cmn = am1*b1n + am2*b2n
That is, the element in row m and column n of C is the sum of the products of the elements in the mth row of A and the nth column of B
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Is it possible to multiply a 3 X 2 matrix and a 2 X 3 matrix?
The first matrix has 3 rows and 2 columns, the second matrix has 2 rows and 3 columns. Two matrices can only be multiplied together if the number of columns in the first matrix is equal to the number of rows in the second matrix. In the example shown there are 3 rows in the first matrix and 3 columns in the second matrix. And also 2 columns in the first and 2 rows in the second. Multiplication of the two matrices is therefore possible.
Can a 3 x 2 matrix be added or subtracted with a 4 x 3 matrix?
No.Two matrices A and B can be added or subtracted if and only if they have the same number of rows and columns. That is a 3 x 2 matrix can be added or subtracted only with another 3 x 2 matrix.
Multiply 2 x 3 x 4?
Question: 2 x 3 x 4 Answer: It's easier to break this down into separate parts. First, multiply 2 x 3 = 6 Then multiply 6 (which is 2 x 3) x 4 = 24 Therefore, 2 x 3 x 4 = 24
Is eigenvalue applicable only to n x n matrices?
The answer is yes, and here's why: Remember that for the eigenvalues (k) and eigenvectors (v) of a matrix (M) the following holds: M.v = k*v, where "." denotes matrix multiplication. This operation is only defined if the number of columns in the first matrix is equal to the number of rows in the second, and the resulting matrix/vector will have as many rows as the first matrix, and as many columns as the second matrix. For example, if you have a 3 x 2 matrix and multiply with a 2 x 4 matrix, the result will be a 3 x 4 matrix. Applying this to the eigenvalue problem, where the second matrix is a vector, we see that if the matrix M is m x n and the vector is n x 1, the result will be an m x 1 vector. Clearly, this can never be a scalar multiple of the original vector.
What 3 numbers can you multiply to get 126?
378
Is it possible to multiply a 2 X 2 matrix and a 2 X 3 matrix?
Yes it is possible. The resulting matrix would be of the 2x3 order.
Is it possible to multiply a 3 X 2 matrix and a 2 X 3 matrix?
The first matrix has 3 rows and 2 columns, the second matrix has 2 rows and 3 columns. Two matrices can only be multiplied together if the number of columns in the first matrix is equal to the number of rows in the second matrix. In the example shown there are 3 rows in the first matrix and 3 columns in the second matrix. And also 2 columns in the first and 2 rows in the second. Multiplication of the two matrices is therefore possible.
Can a 3 x 2 matrix be added or subtracted with a 4 x 3 matrix?
No.Two matrices A and B can be added or subtracted if and only if they have the same number of rows and columns. That is a 3 x 2 matrix can be added or subtracted only with another 3 x 2 matrix.
How do you multiply numbers in a matrix operation?
Multiply the number in matrix one with the corresponding number in matrix two: Matrix 1 Matrix 2 result 2x 3x 4x 6x = 8x2 18x2 4x 5x x 3x 4x2 15x2
Multiply 2 x 3 x 4?
Question: 2 x 3 x 4 Answer: It's easier to break this down into separate parts. First, multiply 2 x 3 = 6 Then multiply 6 (which is 2 x 3) x 4 = 24 Therefore, 2 x 3 x 4 = 24
Solve 2x-3y4 and x 4y 3 by matrix method?
2x - 3y = 4 x + 4y = 3 Write the augmented matrix: 2 -3 4 1 4 3 Multiply the first row by 1/2: 1 -3/2 2 1 4 3 Subtract the second row from the first row: 1 - 3/2 2 0 -11/2 -1 Multiply the second row by -2/11: 1 -3/2 2 0 1 2/11 Multiply the second row by 3/2 and add it to the first row: 1 0 25/11 0 1 2/11 Thus x = 25/11 and y = 2/11 Check:
What do you multiply to get factors of 36?
2 x 2 x 3 x 3
How could you find the number with the prime factorization of 2 times 2 times 3 times 3?
Multiply 2 x 2 x 3 x 3
Is eigenvalue applicable only to n x n matrices?
The answer is yes, and here's why: Remember that for the eigenvalues (k) and eigenvectors (v) of a matrix (M) the following holds: M.v = k*v, where "." denotes matrix multiplication. This operation is only defined if the number of columns in the first matrix is equal to the number of rows in the second, and the resulting matrix/vector will have as many rows as the first matrix, and as many columns as the second matrix. For example, if you have a 3 x 2 matrix and multiply with a 2 x 4 matrix, the result will be a 3 x 4 matrix. Applying this to the eigenvalue problem, where the second matrix is a vector, we see that if the matrix M is m x n and the vector is n x 1, the result will be an m x 1 vector. Clearly, this can never be a scalar multiple of the original vector.
What happens when you multiply two variables with different exponents?
When you multiply two variables with different exponents, the exponents are added. For example, if you multiply x^2 by x^3, the result is x^(2+3) = x^5. Similarly, if you multiply x^3 by x^(-2), the result is x^(3+(-2)) = x^1 = x.
What will be the dimensions of a new matrix formed by multiplying a 2 X 4 matrix and a 4 X 5 matrix?
It will be a 2 x 5 matrix.
What 3 numbers multiply 168?
2, 3 and 7: 2 x 2 x 2 x 3 x 7 = 168
