It's pretty much just like multiplying in base-10 by hand, but you will not have any 'carrying over' to do, since the only possibilities are 0 & 1: 0x0 = 0, 0x1=0, 1x0=0, 1x1=1 (except when you add up the column of numbers after multiplying). An example: Five times six = thirty. So Five is 101 and Six is 110.
00101
x0110
-----
00000
0101
101
--------
11110 ---> in base-10: 16 + 8 + 4 + 2 = 30.
that did not have any carry overs, but if you had to add two or more ones (1+1=10), then a one would carry over to the next column.
Chat with our AI personalities
I assume you mean what is the answer of 1x1 in binary. Obviously the answer to 1x1 is 1. In binary the base ten 'one' is 1. If you mean the 1's in binary you can convert to decimal (they stay 1) and then multiply (getting 1) then convert back to binary (1)
36.62510 = 100100.1012 Multiply 36.625 by 2 until it is an integer, giving 293. This requires 3 multiplies. Convert 293 to binary, giving 100100101. Shift right 3 binary places (balancing the 3 multiplies), giving 100100.101.
Break the Binary number into 3 bit sections from the LSB to the MSB(Right hand site). Then convert the 3 bit binary number to its octal equivalent(Multiply each 3 bit to 2^0 to 2^2). E.g. If the binary value is 1010111110110010 then 001 would be 1, 010 would be 2, 111 would be 7, 110 would be 6, 010 would be 2, etc.
The sum of binary numbers is also a binary number.
To convert a number from base 2 (binary) to base 10 (decimal), you multiply each digit of the binary number by 2 raised to the power of its position from the right, starting at 0. Then, sum up these results to get the decimal equivalent. For example, to convert the binary number 1011 to decimal: 1*(2^3) + 0*(2^2) + 1*(2^1) + 1*(2^0) = 8 + 0 + 2 + 1 = 11.