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let a=b

=>

a^2=a*b

subtract by b^2 on both sides

=>

(a^2)-(b^2)=(a*b)-(b^2)

(a+b)(a-b)=b(a-b)

=>

a+b=b

since a=b

2a=a

=>

2=1......

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Q: How do you prove that one is equals to two?
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