0.036 The significant figures are indicated by the square brackets 0.0[35550], so we round this part of the figure.
The accuracy of the answer is limited to the LEAST significant figures of the input. So if two measured quantities are multiplied or divided, one of which is accurate to only two significant figures, and other to six significant figures, the answer is only accurate to two significant figures. HOWEVER: use all the figures you have for the calculation, and then round your answer to two significant figures. Also, however, remember that if you are multiplying by an actual exact number, as in doubling, the significant figures of that 2 is unlimited, so the answer is only limited by the significant figures of the number you are doubling.
8.0 x 10^3
Two significant figures.
Two significant figures.
0.036 The significant figures are indicated by the square brackets 0.0[35550], so we round this part of the figure.
72 is 72.2 rounded to two significant figures.
8468 rounded to 2 significant figures is 8500
0.004560 to two significant figures results in: 0.0046
3800000
It is 640.
1.0
To round 48100231 Joules to two significant figures, you would round it to 48000000 Joules since the first two significant figures are 4 and 8. The trailing zeros are not significant.
76.51 rounded to 1 significant figures would be 77
72.8 round to two is 73.
2.6
93