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23 = n + (2n-4) = n + 2n - 4

23 = 3n - 4

27 = 3n

9 = n

First number = 9

Second number = 14 [2 x 9 - 4 = 18 - 4 = 14]

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Q: How do you separate the number 23 into two parts so that the second number is 4 less than twice the first number?
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