Oh, dude, it's like you're asking me to do math or something. So, when you simplify 4a times 3b, you just multiply the numbers together and then multiply the variables together. It's like 4 times 3 is 12, and then you have a times b, so the answer is 12ab. Easy peasy, lemon squeezy!
11a+7b-(3b-2a)
(4a - 3b)(4a + 3b)
The equation cannot be solved as there are two unknowns. However it can be simplified and the two unknowns (a and b) expressed in terms of the second unknown. 1) Expressing a in terms of b 4a + 2 = 3b - 5 4a = 3b -7 if desired this could be stated as a = (3b - 7)/4 2) Expressing b in terms of a 3b - 5 = 4a + 2 3b = 4a + 7 if desired this could be stated as b = (4a + 7)/3
-6(a-3b-9c)
3a - 2b
11a+7b-(3b-2a)
3a - 2b
(4a - 3b)(4a + 3b)
To simplify the expression (2(2a + 3b)), you distribute the 2 to both terms inside the parentheses. This results in (2 \cdot 2a + 2 \cdot 3b), which simplifies to (4a + 6b). Thus, the final result is (4a + 6b).
3(a + b) + a = 3a + 3b + a = 4a + 3b
The equation cannot be solved as there are two unknowns. However it can be simplified and the two unknowns (a and b) expressed in terms of the second unknown. 1) Expressing a in terms of b 4a + 2 = 3b - 5 4a = 3b -7 if desired this could be stated as a = (3b - 7)/4 2) Expressing b in terms of a 3b - 5 = 4a + 2 3b = 4a + 7 if desired this could be stated as b = (4a + 7)/3
2a+(-11b)
-6(a-3b-9c)
3a - 2b
4a+3b can not be algebraically simplified. It can be evaluated if you assign values to a and b.
Add them together: 3a+4a-a = 6a
8b -2a