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Earn +20 ptsQ: How do you solve -3x y 5 and -x y - 7?
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If 6x-7 equals 3x plus 5 what is x?
6x-7 = 3x+5 6x = 3x+12 (subtracting -7) 3x=12 (subtracting 3x) x=4 (dividing by 3)
Solve by substitution method y equals -4x - 7 y equals 3x?
y= -4x-7 y=3x 3x= -4x-7 3x+4x=7 7x=7 x=1
3x squared minus 2x when x equals 5?
You fill in for x and solve the equation3(5)^2 - 2(5)15^2 - 10; now solve
-3x2 plus 22x equals 0 how to solve?
-3x2 + 22x = 0 You start by dividing both sides by x: ∴ -3x + 22 = 0 Then rearrange to solve for x: ∴3x = 22 ∴ x = 7 + 1/3
How do you solve this. in parallelogram abcd diagonals ac and bd intersect at e if ac 4x plus 6 and ae equals 3x minus 1 find the value of x?
this is what you would: 4x+6=3x-1 -6 -6 ---- 4x=3x-7 -3x -3x ---- 1x=-7 ---- x=-7
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