All you need to do is substitute the given values of a and c into the equation, then solve for c:
a2 + c2 = b2
102 + 302 = b2
100 + 900 = b2
b2 = 1000
b = √1000
b = 10√10
10 + 10 + 10
-5x + 30 = 20 -5x + 30 - 30 = 20 - 30 -5x = -10 -5x / -5 = -10 / -5 x = 2
10 plus 20 plus 30plus 40 plus 50 equals 150 because 50 plus 40 equals 90 plus 30 =120+20= 140 then + 10 = 150
18 + 10 + 20 + 30 + 15 + 50= 143
x = 6 and y = -2
10 + 10 + 10
x2 + 13x = -30 ∴ x2 + 13x + 30 = 0 ∴ (x + 3)(x + 10) = 0 ∴ x ∈ {-3, -10}
(3,3)
30
It does not help you.
10
-5x + 30 = 20 -5x + 30 - 30 = 20 - 30 -5x = -10 -5x / -5 = -10 / -5 x = 2
If you mean: 10+4r = 30 then it works out that r = 5
10 plus 20 plus 30plus 40 plus 50 equals 150 because 50 plus 40 equals 90 plus 30 =120+20= 140 then + 10 = 150
45 = 30 + m Subtract 30 from both sides: 15 = m
if by thrity equals you mean straight up 30, then the answer is 10.
18 + 10 + 20 + 30 + 15 + 50= 143